;;;; Every ASCII code point, and a few past it, as dyn chars printed one per
;;;; line. The test reads each line back with the reader and wants the same
;;;; code point, so what a char prints as is what reads as it.

(defn main [] i32
  (let [v (vec-new u8)]
    (dotimes [i 128] (push v (u8 i)))
    (let [t (the dyn (str (slice v)))]
      (dotimes [i (length t)] (println (at t i))))
    (let [u (the dyn "é日😀")]
      (dotimes [i (length u)] (println (at u i))))
    (free v))
  0)