;;;; Two macros whose bodies call each other, and the calls are real ones --
;;;; outside any quasiquote, so each has to run while the other is being
;;;; compiled. A defmacro has to be compiled before the call it expands, so a
;;;; ring has no order to be compiled in: neither can go first and neither
;;;; becomes compilable by waiting. The pre-pass names them both.
;;;;
;;;; A call inside a quasiquote is a different thing and is not a cycle. It is
;;;; part of what the macro *answers*, expanded again after it returns, and two
;;;; macros can quasiquote each other forever without either needing the other
;;;; to exist first -- see macro-spin.flan, which is bounded rather than
;;;; refused.

(defmacro ping [args]
  (pong args))

(defmacro pong [args]
  (ping args))

(defn main [] i32
  (ping 1)
  0)