The !-means-mutates convention distinguished nothing — there is no immutable counterpart to contrast with — so every mutating name drops the mark: sort, sort-by, sort-bytes, swap, reverse, append, append-i64, append-f64, encode-rune, split-next, map-remove, map-next, and the test helpers beside them. Two could not simply shed it: map! is map-in-place, because map is the into transform's word and means the non-mutating thing; put! is put-at, because put is the Map builtin. The ?-means-asks convention stays. Dated records keep the old spellings; watch.clj's reset-spies! and the other Clojure names are not ours to rename.
122 lines
5.5 KiB
Plaintext
122 lines
5.5 KiB
Plaintext
;;;; (map-remove m k) — the operation a Map has been missing.
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;;;;
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;;;; Removal is the one map operation that can break the *other* ones: Robin
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;;;; Hood lookups stop at the first empty slot, so a hole punched in the middle
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;;;; of a probe run hides every entry after it, and the entries it hides are
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;;;; found by no test that only removes and asks about what it removed. So the
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;;;; rows below are mostly about the survivors.
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;;;;
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;;;; Odin marks a tombstone and repairs on the next insert; this shifts the run
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;;;; back and stays tombstone-free, which is the arrangement the rest of the
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;;;; file already assumed. A version that punched the hole and left it passes
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;;;; row 1 and fails row 3.
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(defstruct Cell [x i32 y i32])
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(defn main [] i32
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;; (1) The value comes back, the length drops, and the key is gone. An
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;; absent key is None and changes nothing — the same answer get gives, since
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;; a key that was not there is an answer and not a failure.
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(let [m (map-new i32 i64)]
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(put m 1 100)
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(put m 2 200)
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(match (map-remove m 1)
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(Some v) (do (print v) (println "")) ; 100
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None (println "missing"))
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(print (len m)) (println "") ; 1
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(print (has-key? m 1)) (println "") ; false
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(match (map-remove m 1) (Some v) (do (print v) (println "")) None (println "gone"))
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(println (len m)) ; gone, then 1
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(free m))
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;; (2) Removing every entry empties the map, and it is usable afterwards:
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;; the block is still there and the slots are empty rather than poisoned.
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(let [m (map-new i32 i32)]
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(dotimes [i 64] (put m i i))
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(dotimes [i 64] (map-remove m i))
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(print (len m)) (println "") ; 0
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(put m 7 77)
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(match (get m 7) (Some v) (do (print v) (println "")) None (println "?")) ; 77
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(print (len m)) (println "") ; 1
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(free m))
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;; (3) The survivors, which is the row that matters. 2000 entries is eight
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;; grows, so the runs are long and interleaved; removing the even keys and
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;; then asking after every odd one is asking whether any probe run was cut.
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;; A backward shift that stopped one slot early loses entries here and
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;; nowhere else.
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(let [m (map-new i32 i64)]
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(dotimes [i 2000] (put m i (* (i64 i) 3)))
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(let [taken 0]
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(dotimes [i 2000]
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(if (= 0 (% i 2))
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(match (map-remove m i)
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(Some v) (if (= v (* (i64 i) 3)) (set taken (+ taken 1)))
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None (set taken taken))))
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(print taken) (println "")) ; 1000
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(print (len m)) (println "") ; 1000
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(let [lost 0 ghosts 0]
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(dotimes [i 2000]
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(match (get m i)
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(Some v) (if (or (= 0 (% i 2)) (not (= v (* (i64 i) 3))))
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(set ghosts (+ ghosts 1)))
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None (if (not (= 0 (% i 2))) (set lost (+ lost 1)))))
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(print lost) (println "") ; 0
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(print ghosts) (println "")) ; 0
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;; Re-inserting what was taken out puts the length back, through no grow:
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;; the block still has the room the removals freed up.
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(dotimes [i 2000] (if (= 0 (% i 2)) (put m i (* (i64 i) 3))))
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(print (len m)) (println "") ; 2000
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(free m))
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;; (4) A struct key and a string key, so the emitted hash/equality pair is
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;; on the removal path too and not only on get's.
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(let [g (map-new Cell i32)]
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(dotimes [i 20] (dotimes [j 20] (put g (Cell {.x i .y j}) (+ (* i 100) j))))
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(match (map-remove g (Cell {.x 7 .y 9}))
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(Some v) (do (print v) (println "")) ; 709
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None (println "?"))
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(print (has-key? g (Cell {.x 7 .y 9}))) (println "") ; false
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(print (has-key? g (Cell {.x 7 .y 10}))) (println "") ; true
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(print (len g)) (println "") ; 399
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(free g))
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(let [s (map-new string i32)]
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(put s "alpha" 1)
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(put s "beta" 2)
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(match (map-remove s "alpha")
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(Some v) (do (print v) (println "")) ; 1
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None (println "?"))
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(print (has-key? s "beta")) (println "") ; true
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(print (len s)) (println "") ; 1
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(free s))
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;; (5) Iteration after removals answers exactly the survivors. The cursor is
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;; started fresh — a cursor held *across* a removal is invalidated by the
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;; shift, the same way a put that grows invalidates one.
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(let [m (map-new i32 i32)]
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(dotimes [i 100] (put m i i))
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(dotimes [i 100] (if (= 0 (% i 3)) (map-remove m i)))
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(let [cur (i64 0) k 0 v 0 seen 0 sum 0]
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(while (map-next m (addr cur) (addr k) (addr v))
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(set seen (+ seen 1))
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(if (not (= k v)) (set sum (+ sum 1))))
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(print seen) (println "") ; 66
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(print sum) (println "")) ; 0
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(print (len m)) (println "") ; 66
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(free m))
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;; (6) An arena, which refuses can-free. Removal asks the allocator for
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;; nothing and hands it back nothing — a key and a value live inside the one
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;; block the map allocated — so it means here exactly what it means on the
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;; heap, and the region is released whole as always.
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(let [ar (arena-new 1048576)]
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(with-allocator ar
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(let [t (map-new i32 i32)]
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(dotimes [i 300] (put t i (* i 2)))
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(dotimes [i 300] (if (= 0 (% i 2)) (map-remove t i)))
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(print (len t)) (println "") ; 150
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(match (get t 299) (Some v) (do (print v) (println "")) None (println "?")) ; 598
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(print (has-key? t 298)) (println ""))) ; false
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(free-all ar))
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0)
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