The refusal was on the defvar path alone, so (defconst c U (U {.i 1}))
still came back from the emitter as "a global's value must be a
compile-time constant — this one is computed", which is true and says
nothing about unions. Both kinds of global reach the same encoder, so
both get the same message.
It is decided on the checked value rather than on the declared type now,
which is what lets the one initialiser that *is* a constant through: (U
{}) is all-bytes-zero, the same value a declaration with no value gets,
and refusing it would have been telling someone to write the thing they
had written.
Joseph Ferano
aa9a2e03bb