The refusal moves to the checker: Emit.const refused a computed defconst by name while the x86 backend ran it through the startup function behind an .init~once. flag, like a defvar, so the two backends disagreed about the same program. One refusal in Check.const_defconst_init ends that, and it is the only place that can name the way through. The accepted set is unchanged: Tast.const_init's, which is Emit.const's and the x86 data_sym path's, plus the integer arithmetic collect's folding pass has already turned into an Int before the initialiser is looked at. Emit.const's two refusals become a failwith no program reaches; emit_global's gconst || const_init loses its left half; x86 needed no edit, since it never classified by the form. test_flan's infers probe asks Check.expression now that a defconst can no longer wrap an arbitrary expression.
65 lines
3.0 KiB
Plaintext
65 lines
3.0 KiB
Plaintext
;;;; What a re-run does to a global, which is decided by the form that
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;;;; defined it and not by the daemon.
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;;;;
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;;;; A [defvar] is Common Lisp's [defvar]: its initialiser runs only if the
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;;;; variable is not already initialised, so its value survives a re-run. A
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;;;; plain zeroed one always did — .bss is untouched by a second entry into
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;;;; main — and a computed one did not, because the startup function [main]
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;;;; calls ran again from the top and stored the initial value back over
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;;;; whatever the last run had left. A [defconst] whose initialiser is a
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;;;; compile-time constant is written into the image and no startup code
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;;;; reaches it at all, so the question does not arise for it. Since
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;;;; 2026-09-20 there is no other kind: a defconst's initialiser has to be a
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;;;; compile-time constant, refused in the checker so that both backends
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;;;; refuse the same program. Before that the LLVM backend refused a computed
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;;;; one while x86 guarded it at startup like a defvar.
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;;;;
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;;;; So each line printed below is a claim about one of those cases, and the
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;;;; run number is the first of them: [runs] is computed, so before the fix it
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;;;; counted 1, 1, 1.
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(import agent "vendor:agent")
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(defconst base i64 40)
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;; Computed, and the whole reproduction: the initialiser is a call, so it is
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;; lifted into the startup function rather than written into the image.
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(defn start [] i64 base)
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(defvar counter i64 (start))
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;; Zero-valued, which needs no startup at all and must keep needing none.
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(defvar zeroed i64)
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;; A computed dyn global: the map is built by a function, rooted before the
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;; startup function runs, and mutated by every run. Its contents have to
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;; survive a re-run for the same reason [counter]'s value does, and its root
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;; has to survive collection either way.
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(defn table [] dyn {:runs 0})
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(defvar state dyn (table))
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;; The guard flags the fix adds are the compiler's own globals, and they used
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;; to be spelled [.init-once.<name>] — a name a program can write, since [.]
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;; is an ordinary symbol constituent. This one is exactly the old spelling of
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;; [counter]'s flag. It compiles only because the flag is mangled with a [~]
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;; now; before that the dev build died at the assembler with the symbol
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;; defined twice, and the flag's Bool retyped this i64 on the way. It stays
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;; unprinted on purpose — the expected output is what it was.
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(defvar .init-once.counter i64 7)
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(defn main [] i32
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(agent/start "/tmp/flan-dev-rerun-fallback.sock")
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(set counter (+ counter 1))
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(set zeroed (+ zeroed 2))
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(set .init-once.counter (+ .init-once.counter 1))
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(put state :runs (+ (get state :runs) 1))
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(print "counter ") (print counter) (println "")
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(print "zeroed ") (print zeroed) (println "")
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(print "runs ") (print (get state :runs)) (println "")
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(print "base ") (print base) (println "")
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;; Long enough for a client to be served, short enough to park well inside
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;; any watchdog — dev-macro.flan's clock, for its reason.
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(dotimes [i 100]
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(agent/wait 5))
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0)
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